I'm boxing up the Harbinger tonight and since I'm using a Dunlop 18v psu what value resistor would I use for the LED? Do I just double what I usually use because the power is doubled?
N/M 8k2 looks good. :)
This is a good question in general I think. I've seen everything from 1k to 4k7 used (for 9v designs). A larger resistance will limit the current and brightness. I also imagine that different types of LEDS will respond differently to the current going through them. Just typing out loud, never mind me 😊
All depends on how bright you want the LED really. Personally, I use 4k7 on my 9v builds, mainly because I'm using an old stash of UV water clear LEDs and don't want them too bright.
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Quote from: billstein on June 18, 2013, 05:09:54 AM
N/M 8k2 looks good. :)
Sweet, you saved me from posting the same question :)
I always breadboard LED/CLR combo for the particular voltage and LED. In my experience they vary so wildly in brightness (especially waterclear superbrights) that even at 9V sometimes I use 30k+.
Quote from: muddyfox on November 29, 2013, 10:55:22 PM
I always breadboard LED/CLR combo for the particular voltage and LED. In my experience they vary so wildly in brightness (especially waterclear superbrights) that even at 9V sometimes I use 30k+.
Ditto... LED's vary crazily, i've gone as low as 500 ohms and as high as 50K, all running off of nine volts.
Made a box up box (Mark Hammer idea) that switches resistors to find the best match for any particular LED and with ohms law, any supply voltage that will be used. The slider puts a 10k resistor in series with the rotary switch.
(http://i216.photobucket.com/albums/cc305/davent/IMG_4619.jpg)
(http://i216.photobucket.com/albums/cc305/davent/IMG_4614.jpg)
dave