madbeanpedals::forum

Projects => General Questions => Topic started by: Kylianvb on December 28, 2019, 03:30:22 PM

Title: Lowrider 2015 question
Post by: Kylianvb on December 28, 2019, 03:30:22 PM
I built the lowrider a while ago, and I have to say it sounds wonderful and has been on my board ever since. I finally got around to shooting a video-demo for it, but in figuring out how to demo this pedal, I realized that I had no clue what side of the A/B switch actually applies the active filter to the octave-up signal. I definitely hear a difference between the 2 settings, but both sides sound usable and the documentation doesn't specify. I tried to analyze the schematics to figure it out, but my circuit-knowledge ain't quite up to snuff yet, so I figured I'd come ask here rather than end up guessing!

Thanks!
Title: Re: Lowrider 2015 question
Post by: madbean on December 28, 2019, 05:12:07 PM
The square pad of the A/B switch is the active filter output. But, remember that toggle switches activate the pad on the opposing side of the toggle position. That means looking top down, the active filter is the right position of the toggle.
Title: Re: Lowrider 2015 question
Post by: Kylianvb on December 28, 2019, 05:38:27 PM
Thanks a ton for the quick answer, just what I needed!