Specifically how to get the same 16mm pots from mouser as the ones carried by smallbear (http://www.smallbearelec.com/Detail.bok?no=555)? I know they're 1/4" shaft, but mouser has so many different shaft lengths and different options I can't figure out which I should be putting in the cart.
Any help is welcome but if someone has a link that would be great!
thanks
Linear pots: http://www.mouser.com/Search/Refine.aspx?Keyword=313-1000F
Audio pots: http://www.mouser.com/Search/Refine.aspx?Keyword=313-1500F
Thanks man, that is allsome.
If they are out of a particular value can these (http://www.mouser.com/ProductDetail/Alpha-Taiwan/RV170F-10-15R1-B100K/?qs=sGAEpiMZZMtxdMMi52izyjvXBFAE1kmU61%2fyW0rtfqM%3d) be used in a pinch?
Check out these bad boys instead:
Lin: http://www.mouser.com/Passive-Components/Potentiometers-Rheostats/Panel-Mount-Potentiometers/_/N-5g9f?Keyword=313-1210&FS=True
Audio: http://www.mouser.com/Passive-Components/Potentiometers-Rheostats/_/N-5g9c?Keyword=313-1200&FS=True
Datasheet: https://www.mouser.com/catalog/641/687.PDF
12mm instead of 16mm!
A 12mm base would be nice but wouldn't a 15mm shaft length stick up higher than the .33 inch ones from smallbear?
Hey madbean
If I get a 250K Linear pot and put a 170K resistor from lug 1 to lug 3 would that put me in the ballpark of 100kB?
Just making sure I'm doing the math right...
You got it right :)
Another pot question here...Do reverse pots work the same?
Example: If I take a 250kC pot and solder a 5k1 resistor from lugs 1 to 3 does it yield me a 5kC?
thanks
Yep, that should do it.