So I have two circuits that i'd like to reduce the effective range of the pot on.
one is a tube screamer like circuit and i'd like to make the drive control go from 1 to 3 only rather than 1 to 10 (as in 10 = max gain). Is it as easy as raising the value of the 51k off the drive control?
can I just put a resistor in between two lugs of a pot or in series with one lug?
Say lug 3 is to GND on a 500k pot and I want only 250k to 500k worth of range: what do I do?
Quote from: B_of_H on January 12, 2011, 12:49:10 PM
Say lug 3 is to GND on a 500k pot and I want only 250k to 500k worth of range: what do I do?
put a resistor in series with lug 3 to ground. this will make sure that there is never zero resistance between lug 2 and ground and therefore there will always be voltage there (since ground is 0 V). Without doing the math, intuitively i think it'll be 250k resistor to get a the sort of divider you're looking for (that's unverified, I can try and work it out later if you need).
Quote from: B_of_H on January 12, 2011, 12:49:10 PM
So I have two circuits that i'd like to reduce the effective range of the pot on.
one is a tube screamer like circuit and i'd like to make the drive control go from 1 to 3 only rather than 1 to 10 (as in 10 = max gain). Is it as easy as raising the value of the 51k off the drive control?
Since the drive control is in a feedback loop, and MORE resistance in a loop INCREASES the output, you need to remove some resistance. I don't have time to do the math right now, but I think you should get a pot that's about 1/3 the resistance of the current one.
thanks, yeah I did some tinkering yesterday and played with different ideas. I appreciate the input.