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It's been a long time but the total recall consumes areound 50-75ma depending on how the delay pot is set. It is DEFINITELY under 100ma consumption.

Thank you, so resistors I recommended are sufficient.

My Religion of Ufo-fils of Saint Landing doesn't celebrate Christmas :@)

Output is desired 15V. It is ok.

Consider this. Generally, separate power for modulators and clock generators from signal power rail. For all power lines - plus, minus, ground. If pcb concept allows it, of course.

BTW, that +Va output will be little noisy because of transistor transient characteristic. So, I would block this power output against ground with come caps - cca 10uF electrolytic, paralelly with 100nF ceramic.

I would say it this way: if opamps in audiosignal have 9V power, then it is better, when driving values, that makes some modulation signals, are little lower, for example cca 8V. So, top of this driving curves or clock rates has some "reserve" not to clip and so distort process of modulation.
Transistor gives here stronger current to power rail, than divider from resistors. This is the simplest way how to get little lower voltage output without using opamp source with some divider at input.

Yes it goes from that emitter of Q in left corner. It gives slightly lower value, but stabilized. So, modulator has little lower values going to driving process, not overhelming values at opamps in signal track. It is very frequently used hack - modulation circuit has lower top values not to overfuell modulation pins in opamps.

Maybe simulator will show values here. I use Caneda, and I can see. But not now, too busy.

Unhapilly I don't know what is comperhensive current consumtion of all vehement. So, I don't know what power is lost at this R57. Maybe Madbean will know. If your power has 34V, and after this resistor you have 29V, at this resistor is lost 5V with some current, I just don't know. This will give power lost in heat (current x voltage) Let's say that 100mA is proper value. With 5V lost at R57 it will give 500mW lost in heat. R57 must have mimimally 2x higher calibration - so here it is 1W. But if you will change polarity (by mistake), that protecting diode D1 will make shortage of this at ground, to protect circuit from bad polarity. Not to be D1 damaged, this resistor must lower current thru this diode at safe value. If you will use 34V, and diode can withstand 200mA (catalogue value), you will need 160 Ohm minimal value. But better raise this value for some safety at cca 270 Ohm. (Simplyfied, power lost at this resistor 160 Ohm when shortage, is 34V x 200mA= 7W! When resistor is 270 Ohm, lost power is cca 4W. For a moment it can protect your system. Dependig at max. current that power source can really give, and it's anti-shortage protection, of course!

I hope I didn't bore you with my article :@) I recommend to use 270 Ohm, 4W.

Stabil or stabilizator - yes it is another word for your regulator, thouhg it doesn't regulate any values, only makes one value firm, independently at input values. I am sorry for this confusing you. The "butt" of stabil is here pin 1, sitting at ground. Against this pin you will read all values. So, at input pin 2 you will have some voltage from power supply - you said that you use cca 34V. So here you will have cca 30V (after input resistor). At pin 3 will be output, against ground. So, here 15V. All according picture I attached. BTW, if you use somewhere 34V, filtering caps must have by cca 25% voltage values higher. Here for 34V at input you may need use caps for 40V or higher.

At middle (pin2) there must be power input from outer power source. Those -30V or so... Separated from input only by resistor. At output (pin3) must be -15V. I am affraid that or this resistor or even stabil are damaged.

Here is stil one thing: caps at power input are calibrated for 25V in list of details, so if you put here 35V, they are very probably damaged, shooting power from source at zero. And "duting" power source to shortage.

I guess it is about BIASing. Making current source for transistors working as amp stages. It gives better qualities for stable current no matter how gate - drain of that j-fet is set. Results in much lower noise and distortion at D-S pass. Something similar I encountered in electret mics current sources. You can sit here only simple resistor for power for mic. But you can put here such a current drived source, so that j-fet inside of mic can work under stable regime, which is primarly impossible for very specific setting of capacitor charge in that mic. See pict I attached.

I don't know if I have proper schematic, but if D1 was sat backwards, it is probably damaged - that would explain, why at stabil is not power. BTW, 34V is almost top of what you can put at this stabil input. But now, if everything is ok, there must be at input of stabil cca -30V, at ground 0V and at output -15V. Plus minus. See picture. Those caps are different in this schema but it is not important now - it is only mooster. Power value recomended is -24V - this is what that input resistor 240 Ohm is calibrated on. Otherwise, for -34V put here something around 360 Ohm.

Just take multimeter with resistance meter (glyph with diode) and reflow all tracks from utmost points to others, to controll if tracks are consistent. By eye you won't see it.

Hi, Bassybeats, it's only about current going thru Lamp or LED if engagedn instead this lamp. If you have 15V power and LED asks 20mA, to shine fully, you will put serially LED and resistor R=U/I. This will give 750 Ohms. So, here use 680Ohm and together with pot GAIN and R53 set at 82 Ohm, it will give this current. Maybe I should raise Gain pot. It is important, that when pot Gain is at minimum, R53 and LED resistor will give 750 Ohms for this setting. If you will use 4 LEDs in paralell setting, one for every LDR, current will raise at 80mA, so you will have final resistance not 750 ohms, but 750/4. So I would use here resistor 180 Ohms. But for 2W.